Sentence Examples


  • Dibromcotinine on hydrolysis yields oxalic acid, methylamine and 0-methyl pyridyl ketone: C10H10Br2N20+3H20+0= H2C204-ECH 3 NH 2 +C 5 H 4 N 000H 3 +2HBr; whilst dibromticonine yields methylamine, malonic acid and nicotinic acid: C10H8Br2N202+ 4H20=CH 3 NH 2 +CH 2 (CO 2 H) 2 +C 5 H 4 N CO 2 H+2HBr, or if heated with zinc and caustic potash, methylamine and pyridyl-ay-dioxybutyric acid.
  • A 2 y2 a2 /32_ a2 y2 a2 -, 9_a2 72 - a2 a 1 3 y = a fl - a y - a - y - a I 1111 0 0 (0 - a)(7 - a)I i ay 1 a I = (a - 7)(7 - a)I 130771-al = (a - a) (7 a)(0-7).
  • By similarly transforming the binary n ic form ay we find Ao = (aI A 1 +a2 A2) n = aAn A l = (alAi - I -a 2 A 2) n1 (a1�1 +a2m2) = aa a � - A i n-1 A2, n-k k n-k k n-k k A = (al l+a2A2) (al�1+a2�2) = a A � =A 1 A2, so that the umbrae A1, A 2 are a A, a � respectively.
  • There may be a number of forms ay,bi,ci,...
  • -2 _ ab 2an-2bn-2Crz z x () x x x, Each term on the right-hand side may be shown by permutation of a, b, c to be the symbolical representation of the same covariant; they are equivalent symbolic products, and we may accordingly write 2(ac) (bc)ai -1 bi -1 cx 2 =(ab)2a:-2b:-2c:, a relation which shows that the form on the left is the product of the two covariants n (ab) ay 2 by 2 and cZ.
 

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