If we denote the critical volume, pressure and temperature by Vk, Pk and Tk, then it may be shown, either by considering the characteristic equation as a perfect cube in v or by using the relations that dp/dv=o, d 2 p/dv 2 =o at the critical point, that Vk = 3b, Pk= a/27b2, T ic = 8a/27b.
+mp4dp4 +...) =exp Mp g dp 4+ï¿½ï¿½ .
Recalling the formulae above which connect s P4 and a m, we see that dP4 and Dp q are in co-relation with these quantities respectively, and may be said to be operations which correspond to the partitions (pq), (10 P 01 4) respectively.
The direction of F is given by the following construction: Trisect OP at C, so that OC =OP/3; draw CD at right angles to OP, to cut the axis produced in D; then DP will be the direction of the force at P. For a point in the axis OX, 0 =0; therefore cos 0 = 1, and the point D coincides with C; the magnitude of the force is, from (14), Fx=2M / r3, (15) its direction being along the axis OX.
How would you define dp? Add your definition here.